Question

a body of mass 10 kg is thrown up with a velocity 98 metre per second simultaneous another is dropped from a tower after 2 second their moment are found to be same in magnitude then the mass of the free falling bodies ​

Answer 1

Answer:

Mass of the free falling body is 50 kg

Explanation:

$m_{1}=10kg\\v_{1}=98 m/s\\t=2 s$

velocity of the second body

$v_{2}=u_{2}+at$

$v_{2}=0+9.8 \times 2\\v_{2}=19.6 m/s$

moment are found to be same after 2 seconds,which is given by

$m_{1}v_{1}=m_{2}v_{2}\\10\times 98=m_{2}\times 19.6\\m_{2}=\frac{980}{19.6} \\m_{2}=50 kg$