Question

A body of mass 10 kg moving with constant velocity of 10 m/sec. After 10 sec
the work done by a body is:
A) 500 J
B) 5 KJ
C) 0.5)
D) Zero
​

Answer 1

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkk

Answer 2

Answer:

Here is ur answer-

W=KE

f

−KE

i

W=KE

f

−

2

1

mv

2

F−dx=KE

f

−

2

1

×10×10

2

−0.1xdx=KE

f

−500

0.1∫

20

30

xdx=KE

f

−500

0.1[

2

x

2

]

20

30

=KE

f

−500

=

2

0.1

[(30)

2

−(20)

2

]=KE

f

−500

−25=KE

f

−500

KE

f

=475J

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