a body of mass 10 kg suspended from a wire of length 4 m and radius 1 by under root 5 mm calculate the stress.
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Of the mass is moved to one side and released from the ... of wire then find the maximum extension in the length of the ... given Ysteel=2 x 10^11 N/m^2 area of cross.
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Answer:
Force on the wire =mg=100N
Ans a -
Stress (σ)= F/A = 100/4×10^-6
= > 25×10^6 pa
Ans b-
Strain (ϵ)= σ/y = 25×10^6 / 2 × 10^11
=> 12.5 × 10-5
Ans c-
Elongation (Δl)=strain×length=37.5×10 ^−5 m
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