A body of mass 100 kg is lifted up by 10 m. find : (d) the amount of work done, (e) potential energy of the body at that height, (g = 10 ms-2)
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work done by external force
W = + mgh
= 100x10x10
= 10000 J
U = U' + mgh
where U ' is the potential energy at reference
U = U' + 10000 J
if PE at reference (let here ground) is zero then
U = 10,000 J
W = + mgh
= 100x10x10
= 10000 J
U = U' + mgh
where U ' is the potential energy at reference
U = U' + 10000 J
if PE at reference (let here ground) is zero then
U = 10,000 J
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