Question

A body of mass 100g is at rest on a smooth surface. A force of 0.2 N acts on it for 5s . Calculate the distance travelled by the body

Answer 1

Answer:

F=m×a=0.2

100×a=0.2

a=0.2÷100

a=0.002ms-2

s=ut+1/2at^2

s=0×5+1/2×0.002 ×5×5

s=0+1/2×0.05

s=0.025m

Explanation:

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