A body of mass 100g is at rest on a smooth surface. A force of 0.2 N acts on it for 5s . Calculate the distance travelled by the body
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Answer:
F=m×a=0.2
100×a=0.2
a=0.2÷100
a=0.002ms-2
s=ut+1/2at^2
s=0×5+1/2×0.002 ×5×5
s=0+1/2×0.05
s=0.025m
Explanation:
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