Question

A body of mass 10kg fall freely from a certain height find the force acting on it in SI and technical unit (g=9.81 N)?
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Answer 1

$\pink {\frak{Given}} \begin{cases} \: \sf mass \: of \: the \: body \: (m) = 10 \: kg. \\ \\ \sf acceleration \: due \: to \: gravity \: (g) = 9.8 \: ms ^{ - 2} \\ \\ \sf force \: (F) = \: ? \end{cases}$

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$: \implies \displaystyle \sf \: Force = mass \times Acceleration$

$: \implies \displaystyle \sf \: Force = mg$

$: \implies \displaystyle \sf \: Force = 10 \: kg\times 9.8 \: ms^{ - 2}$

$: \implies \displaystyle \sf \: Force = 98 \: kg.ms ^{ - 2}$

$: \implies \underline{ \boxed{ \displaystyle \sf \: \bold{Force = 98 \: N.}}}$

$\therefore \underline{ \displaystyle \sf \: Force \: acting \: on \: the \: body \: is \: 98 \: Newton.}$

Answer 2

Answer:

$\sf \underline {Question}$

A body of mass 10kg fall freely from a certain height find the force acting on it in SI and technical unit (g=9.81 N)?

$\sf \underline {Given}$

mass of the body(m)=10kg.

acceleration due to gravity(g)=9.8ms

$\huge \sf {Formulae}$

Force = Mass × acceleration

Force = 10kg×9.8ms-²

Force = 98 kg.ms -²

$\huge \fbox {The force = 98 Newton}$