a body of mass 10kg initially at rest acquires velocity of 10m per s what is the work done
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Work done = kinetic energy K.E.= 1/2 mv^2 W= 1/2 * 10* 10 * 10 W = 500J
ramu395:
is it positive or negative work
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Given: mass of the body- m = 10kg
initial velocity- u = 0 (at rest)
final velocity - v = 10m/s
To Find: work done - W = ?
Solution:
Formulas used:
- Work energy theorem - the difference of kinetic energy gives work done.
- ΔW = K' - K (K' = final kinetic energy, K = initial kinetic energy)
- Kinetic energy = 1/2 × m × v²
Applying the above formulas:
ΔW = 1/2 × m × v² - 1/2 × m × u²
ΔW = 1/2 × 10 × 10² - 1/2 × 10 × 0²
ΔW = 1/2 × 10 (10² - 0²)
ΔW = 5 × 10²
ΔW = 500J
Hence, work done by the body = 500J
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