Question

a body of mass 10kg is displaced from point A(2,1,3) to B(3,3,4) ubder the effect of force of magnitude 20N in the direction of 6icap +8jcap. Calculate work done by force

Answer 1

Given,

[tex] \vec{r_1} = 2i + j  + 3k \\ \\ \vec{r_2} = 3i + 3j + 4k  \\ \\   displacement(\vec{d}) = \vec{r_2} - \vec{r_1}  \\ \\ \vec{d} =  3i + 3j + 4k - (2i + j  + 3k) \\  \\  \vec{d} = i + 2j +k  \\ \\  F = 20(6i + 8j)  \\ \\ \text{We know that,} \\ \\ Work  = \vec{F}.\vec{d} \\ \\ W =  20(6i + 8j) \ . \ ( i + 2j +k) \\ \\ W = 20 \times (6 + 16) \\ \\ W =  440 N [/tex]

Answer 2

Answer:

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