Question

A body of mass 10kg is kept at rest. If 50N force is applied on it for 20s. What will be the

work done?​

Answer 1

Answer:

hey..!

Explanation:

Here, F= -50 N (-ve sign for retardation) m=10 kg, u= 10 ms

−1

, v=0

As F=ma ∴a=

m

F

=

10kg

−50N

=−5ms

−2

Using v=u+at ∴t=

a

v−u

=

−5ms

−2

0−10ms

−1

=2s

Answer 2

Answer:

Here, F= -50 N (-ve sign for retardation) m=10 kg, u= 10 ms

−1

, v=0

As F=ma ∴a=

m

F

=

10kg

−50N

=−5ms

−2

Using v=u+at ∴t=

a

v−u

=

−5ms

−2

0−10ms

−1

=2s

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