A body of mass 10kg is under the action of 138N on horizontal surface if coefficient of friction in b/w the surfaces in one the distance it travels in 10s in metre is
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F-Fr = ma
Fr =F-ma =138- 10a=meu *mg =meu *10*10=100meu
Meu =1/(1/2*a*100)=1/(50a)
a =1/(50*meu
Now put the value of a in 1st equation
Fr =F-ma =138- 10a=meu *mg =meu *10*10=100meu
Meu =1/(1/2*a*100)=1/(50a)
a =1/(50*meu
Now put the value of a in 1st equation
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