A body of mass 10kg starts from rest and rolls down an inclined plane it rolls down 10m in 2sec calculate what is the acceleration attained by the body, what is the force acting on the body and what is the velocity of the body
Answers
Answered by
0
velocity is 5m/s and force20N
Answered by
0
Answer:
Given ,
m =10kg
initially velocity (u) = 0m/s
distance (s) = 10 m
time( t) = 2sec
Explanation:
To find,
acceleration attend by the body
force acting on the body
velocity of body
applying position time equation
s = ut + 1/2 at²
10 = 1/2 *a*2²
= 1/2 *4*a
10 = 2a
a = 5m/s²
now
force = mass * acceleration
f = (10*5) N
f = 50 N
now applying velocity time equation
v = u+ at
v = 0 + 5*2
v = 10 m/s
Similar questions