A body of mass 120 kg is taken vertically upward to reach the height of 5 m. Calculate the work done.
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work done = F * S
F = mg = 120* 9.8 = 1176 N
s = h = 5 m
work done = F *S = 1176 * 5 = 5880 joule
F = mg = 120* 9.8 = 1176 N
s = h = 5 m
work done = F *S = 1176 * 5 = 5880 joule
bhavyadeep31yad:
i told take g= 10 m/s
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Work done against gravity is mgh m=120 kg h=5m g=9.8 m/s square 120 x 5 x 9.8 =5880 kgm^2/s^2
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