a body of mass 1kg is kept at rest . A constant force of 6n starts acting on it , find the time taken by the body to move through a distance of 12 m
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firstly we must remember
F = ma
where, F = force
m = mass
a = acceleration
force is given in the question as 6n and mass as 1 kg, we can find acceleration with this, thus
6 = 1 x a
∴ a = 6÷1
∴a = 6m/sec²
now we have to use equations of motion to solve this.
S = ut + 1/2at²
where S = distance travelled
u = initial speed
a = acceleration
t = time taken
as the object was at rest initially, thus initial speed, u = 0
so, S = 0×t +1/2at²
∴ S = 1/2at²
S = 12m (given in question) and a = 6m/sec² (solved above)
12m = 1/2 ×6t²
solving this we get; t² = 4sec²
∴ t = 2 sec
F = ma
where, F = force
m = mass
a = acceleration
force is given in the question as 6n and mass as 1 kg, we can find acceleration with this, thus
6 = 1 x a
∴ a = 6÷1
∴a = 6m/sec²
now we have to use equations of motion to solve this.
S = ut + 1/2at²
where S = distance travelled
u = initial speed
a = acceleration
t = time taken
as the object was at rest initially, thus initial speed, u = 0
so, S = 0×t +1/2at²
∴ S = 1/2at²
S = 12m (given in question) and a = 6m/sec² (solved above)
12m = 1/2 ×6t²
solving this we get; t² = 4sec²
∴ t = 2 sec
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