Question

A body of mass 1kg is kept at rest.A constant force of 6N starts acting on it.Find the time taken by the body to move through a distance of 12m.

Answer 1

Answer :

• Find the time taken by the body to move through a distance of 12 m is 2 sec

Solution :

First we need to find the acceleration of the body

we know that ,

$\bigstar\boxed{\pink{\mathtt{F=ma}}}$

as per the given data ,

• mass of the body (m)= 1 kg
• force acting on the body(F) = 6 N

$\rightarrow\mathtt{6=1 \times a}$

$\rightarrow\mathtt{\red{a=6\dfrac{m}{s^{2} }}}$

_____________________

In order to find the time taken by the body lets use the second kinematic equation ,

$\bigstar\boxed{\pink{\mathtt{s=ut+\dfrac{1}{a}at^{2} }}}$

here,

• s= distance=12 m
• u=initial velocity =0 m/s (rest)
• t= time taken =?
• a= acceleration =6 m/s^s

$\rightarrow\mathtt{12=0 + \dfrac{1}{2} \times6 \times t^{2} }$

$\rightarrow\mathtt{12= 3 \times t^{2} }$

$\rightarrow\mathtt{t^{2} =\dfrac{12}{3}}$

$\rightarrow\mathtt{t^{2} =4}$

$\rightarrow\mathtt{\red{t=2 sec }}$

Answer 2

ANSWER➡️

2 sec

here is use two formulas

1). F=ma

where F is force, m is mass, a is acceleration

2).

$s = \frac{1}{2} \: a {t}^{2}$

where s is distance,t is time

ONE THING TO KEEP IN MIND IS THAT

AS U IS ZERO SO UT WILL BECOME ZERO THAT'S WHY I NEGLECT IT AND NOT CONSIDER IT IN THE FORMULA