A body of mass 1kg is moving with velocity 30 m/s due north . It is acted on by a force of 10 N due west for 4 seconds. Find the velocity of the body after the force ceases to act.
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Ft=âmv. (vectors)
Taking north as positive x
(-10j)4=[(v1i+v2j)-(30i)]1
v=30i-40j
Taking north as positive x
(-10j)4=[(v1i+v2j)-(30i)]1
v=30i-40j
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