Question

A body of mass 1kg is placed at a distance of 2m from another body of mass 10kg at what distances be placed so that of 1kg another body of mass 5kg be placed so that net force of gravitation acting one the body of mass 1kg is zero?

Answer 1

[5kg]……(x)……[1 kg]………(2 m)………[10 kg]

F1 = F2
GMm / x^2 = GM’m / (2)^2
M / M’ = [x / 2]^2
5 / 10 = [x / 2]^2
1 / √2 = x / 2
x = √2 m

5kg object should be placed √2 m from 1 kg away from 10 kg