Question

A body of mass 1kg is projected from ground at an angle of 30 with horizontal on a level ground at a speed 50m/s. The magnitude of change in momentum of the body during its flight is

Answer 1

You need to know bro that the final velocity with which tue projectile strikes the ground is equal to the velocity with which it was projected. Also I had subtracted the initial momentum from the final momentum using vector law of addition, by adding pfinal to -pinitial. In the triangle you can apply the sum of all angles to be 30 degree and findtye angle between pfinal and -pinitial.

Answer 2

Answer:

Change in momentum is nothing but m(v-u)

where m=mass,

u=initial velocity,

v=final velocity

This is a case of projectile motion.So,final velocity must be zero and initial velocity is given as 50 m/s

Therefore, 1(0-50)=-50 (negative because particle is deceleratingxplanation: