Question

A body of mass 2 gram performs linear simple harmonic motion is a restoring force acting on it is 3 newton when it is 0.06 from the mean position the period of simple harmonic motion is​.....

Answer 1

I don't know please ask others you know the answer

Answer 2

Time period of body is 0.04 s.

Given :

Mass of object ,  $m=2 \ gm=2\times 10^{-3}\ kg.$

Position of object from mean position , x = 0.06 m ( it is not given , so taking in SI units).

Restoring force acting at a position  x , F = 3 N .

We know,

$F=k\times x\\3=k\times 0.06\\k=\dfrac{3}{0.06}=50\ N/m.$

Now, Time period of a given object doing SHM is :

$T=2\times \pi\times \sqrt{\dfrac{m}{k}}$

Putting values of m and k in above equation, we get :

$T=2\times \dfrac{22}{7}\times \sqrt{\dfrac{2\times 10^{-3}}{50}}=0.04 \ s.$

Learn More :

Simple Harmonic Motion

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