Question

A body of mass 2 kg and 8000 kg/m^3 is completely immersed in liquid of density 800 kg/m^3.Find the force of buoyancy on it.​

Answer 1

Answer:

The buoyancy force exerted by a liquid on an object dipped in it will be

F = ρgV

where ρ is the density of the liquid, V is th volume of the object immersed in the liquid and g is the acceleration due to gravity.

So

here

ρ = 800 kg/m3

g =10 m/s2

and V = mass/density = 2/8000 = 2.5 X 10-4 m3

thus,

F = 800 X 10 X 2.5 X 10-4 = 8 X 2.5 X 10-1

or

F = 2 N

Step-by-step explanation: