Question

a body of mass 2 kg having a velocity of 2ms^-1 is brought to rest within a distance of 2m the force acting on the body is​

Answer 1

Answer:

Given that,

Mass m=2kg

Initial velocity u=0m/s

Final velocity v=20m/s

Time t=4s

Now, the acceleration is

v=u+at

a=

t

v−u

a=

4

20

a=5m/s

2

Now, the force is

F=ma

F=2×5

F=10N

Now, the displacement is

s=ut+

2

1

at

2

s=0+

2

1

×5×16

s=40m

Now, the work done is

W=F⋅s

W=10×40

W=400J

Now, the power is

P=

t

W

P=

2

400

P=200watt

Hence, the power is 200 watt

Answer 2

Answer:

-2 N

Explanation:

v² = u² +2 as

0 = 2² + 2 a 2

a = ( 0 - 4 ) / 4

a = -1 m / s²

F = ma

F = -1 × 2

F = -2 N

HOPE IT HELPS

PLEASE MARK AS BRAINLIEST