A body of mass 2 kg is acted upon by two forces vecD_(1)=(2hati+3hatj)N and vecF_(2)(-2hatk+3hatj)N. If the body is displaced from A(3m, -2m, 1m) to B (-1m, +2m,-3m), then work done on the body is
Answers
Answer:
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Explanation:
Let us apply the parallelogram law of vectors to find the resultant of the forces.
F
net
=
F
1
2
+F
2
2
+2×F
1
F
2
cosθ
Given: F
1
=1,F
2
=1 and θ=60
0
So, F
net
=
(1)
2
+(1)
2
+2×1×1×cos60
0
=
1+1+2×1/2
=
3
N
Now
F=ma
or, a=
m
F
=
2
3
Let us apply the parallelogram law of vectors to find the resultant of the forces.
F
net
=
F
1
2
+F
2
2
+2×F
1
F
2
cosθ
Given: F
1
=1,F
2
=1 and θ=60
0
So, F
net
=
(1)
2
+(1)
2
+2×1×1×cos60
0
=
1+1+2×1/2
=
3
N
Now
F=ma
or, a=
m
F
=
2
3
m/s
2
Thus, the net acceleration of the body is
2
3
m/s
2
m/s
2
Thus, the net acceleration of the body is
2
3
m/s
2