A body of mass 2 kg is moving with a velocity 8 metre per second on a smooth surface if it is to be brought to rest in 4 second then the force to apply days
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17
initial velocity is 8m per second
final velovity is 0
time=4second
acceleration =0m/sec-8m/sec/4sec
=-8m/sec/4sec=-2m/s²
so a =-2m/s²
now force applied=mass*acceleration
=2kg*-2m/s²=-4kgm/s²=
-4newton
final velovity is 0
time=4second
acceleration =0m/sec-8m/sec/4sec
=-8m/sec/4sec=-2m/s²
so a =-2m/s²
now force applied=mass*acceleration
=2kg*-2m/s²=-4kgm/s²=
-4newton
Answered by
7
Explanation:
a=0-V0/t
=0-8/4
= -2m/s
force to be applied
F=ma
=2×2
=4N
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