Question

A body of mass 2 kg is moving with a velocity 8 metre per second on a smooth surface if it is to be brought to rest in 4 second then the force to apply days

Answer 1

initial velocity is 8m per second
final velovity is 0
time=4second
acceleration =0m/sec-8m/sec/4sec
=-8m/sec/4sec=-2m/s²
so a =-2m/s²
now force applied=mass*acceleration
=2kg*-2m/s²=-4kgm/s²=
-4newton

Answer 2

Explanation:

a=0-V0/t

=0-8/4

= -2m/s

force to be applied

F=ma

=2×2

=4N