A body of mass 2 kg is moving with momentum 4 kg m/s. A force of 2 N acts on it in the direction of motion for 5 s. The increase in kinetic energy is
as fast as possible
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Answer:
t=5s
p=mv
4=2×v
v=2m/s
as F=2N
a=2/2m/s²= 1m/s²
KE=1/2mv²
KEi=4J
now ,t=5s
v f =u+at
vf=g+1×5
=5m/s²
KEf=1/2×2×5
KEf=5J
△KE=5-4
=1J
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