A body of mass 2 kg is projected with a speed of 20 metre per second at an angle of 60 degree with the horizontal from the surface of the earth.Torque of its weight about the point of projection at t= 2 second
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Torque = T = 692.7822 N
Explanation:
Mass = m = 2 kg
Weight = W = mg = (2)(9.81) = 19.62 N
Initial velocity = V = 20 m/s
Angle = θ = 60 degrees
First we have to find the range of the projectile which is actually a moment arm. So,
Range of projectile = r = V^2 sin2θ/g = (20)^2 sin2(60)/9.81 = 35.31 m
Torque = T = rF = (35.31)(19.62)
Torque = T = 692.7822 N
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Answer:
,689.7822
Explanation:
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