Question

a body of mass 2 kg is thrown up with a velocity 30 metres per second find the potential energy of the body at the highest point

Answer 1

Heya user !!

Here's the answer you are looking for

Mass of the object (m) = 2kg

Initial velocity (u) = 30m/s

Final velocity (v) = 0 (at the heighest point)

Acceleration (a) = -g = -10m/s²

Using the 3rd equation of motion,

v² - u² = 2as

0² - (30)² = 2(-10)(s)

s = 900/20 = 45

So, height reached by the body is 45m

➡️ Therefore, potential energy at the heighest point

= mgh

= 2 (10) (45)

= 900 J (ans)



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Answer 2

Answer:

Explanation:

user !!

Here's the answer you are looking for

Mass of the object (m) = 2kg

Initial velocity (u) = 30m/s

Final velocity (v) = 0 (at the heighest point)

Acceleration (a) = -g = -10m/s²

Using the 3rd equation of motion,

v² - u² = 2as

0² - (30)² = 2(-10)(s)

s = 900/20 = 45

So, height reached by the body is 45m

➡️ Therefore, potential energy at the heighest point

= mgh

= 2 (10) (45)

= 900 J (ans)