A body of mass 2 kg is thrown vertically upward with an initial velocity of 20 metre per second what will be its potential energy at the end of 2 second. (assuming G is equal to 10 metre per second)
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Potential energy due to gravitational force is given as, P.E. = mgh

We have, u = 20 m/s, a = –10 m/s2, t = 2 s, s = h1
Hence potential energy after 2s, P.E.1 = (2 kg) � (10m/s2) � (20 m) = 400 J

We have, u = 20 m/s, a = –10 m/s2, t = 2 s, s = h1
Hence potential energy after 2s, P.E.1 = (2 kg) � (10m/s2) � (20 m) = 400 J
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I am doing it in copy u can see pic for ur answer
The mass is 2kg I wrote 20kg by mistake
so
potential energy= 2*-10*20= -400 joule( negative sign indicates work done against gravity which is equal to potential energy.)
The mass is 2kg I wrote 20kg by mistake
so
potential energy= 2*-10*20= -400 joule( negative sign indicates work done against gravity which is equal to potential energy.)
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