Two numbers are 20% and 25% less than a third number respectively. how much % is the second number less than the first number ?
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Answered by
16
Let A, B, C be three numbers.
Let B is 20% less than A , and C be 25% less than A.
Let A be x, then
B = x - 20% of x = x - ( 20/100 )x = 80x/100 = 0.8x
C= x - 25% of x = x- 25/100x = 75x/100 = 0.75x
Now we have to find out how much % C is less than B so
08x075x08x100
005x08x100
10016
625
(answer)
Let B is 20% less than A , and C be 25% less than A.
Let A be x, then
B = x - 20% of x = x - ( 20/100 )x = 80x/100 = 0.8x
C= x - 25% of x = x- 25/100x = 75x/100 = 0.75x
Now we have to find out how much % C is less than B so
08x075x08x100
005x08x100
10016
625
(answer)
Answered by
14
Let 3rd number is 100 then the 1st and 2nd no are respectively 80 and 75.
Then the 2nd number to be enhanced = 5/80 × 100 = 25/4
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