Question

Two numbers are 20% and 25% less than a third number respectively. how much % is the second number less than the first number ?

Answer 1

Let A, B, C be three numbers.
Let B is 20% less than A , and C be 25% less than A.
Let A be x, then
B = x - 20% of x = x - ( 20/100 )x = 80x/100 = 0.8x
C= x - 25% of x = x- 25/100x = 75x/100 = 0.75x
Now we have to find out how much % C is less than B so
08x075x08x100
005x08x100
10016
625
(answer)

Answer 2

Let 3rd number is 100 then the 1st and 2nd no are respectively 80 and 75.

Then the 2nd number to be enhanced = 5/80 × 100 = 25/4