A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What will be is
potential energy at the end of 2 s? (Assume g = 10 m/s2).
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13
Answer:
Given,
Mass of the body, m = 2kg,
Initial velocity, (u) = 20 m/s,
Time, (t) =2s,
Acceleration due to gravity, g = 10 m/s.
Let the height at the end of 2s = d
We know that,
d = ut + 1/2at2
d = 20 x 2 + 1/2 x (-10) x (2)2
d = 40- 20
d = 20m
(g is taken as negative because it is acting in the direction opposite to the direction of motion)
Potential Energy, P.E = mgh
= 2 × 10 × 20
= 400 J.
Anonymous:
Well Done
Answered by
6
Initial velocity is 20 m/s , mass of body is 2 kg.
So lets find out the height upto which the ball goes after 2 seconds :
Potential Energy is the Gravitational Energy possessed by the virtue of its position with respect to the position in the Earth's Gravitational Field.
PE = m × g × h = 2 × 10 × 20 = 400 J.
So final answer is 400 J
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