A body of mass 2 kg is thrown vertically upwards with an initial velocity of 25m/s find its maximum potential energy
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Potential energy due to gravitational force is given as, P.E. = mgh
We have, u = 20 m/s, a = –10 m/s2, t = 2 s, s = h1
Hence potential energy after 2s, P.E.1 = (2 kg) � (10m/s2) � (20 m) = 400 J
Hope this helps you.
We have, u = 20 m/s, a = –10 m/s2, t = 2 s, s = h1
Hence potential energy after 2s, P.E.1 = (2 kg) � (10m/s2) � (20 m) = 400 J
Hope this helps you.
Answered by
1
Mass of a body is given 2 Kg
Initial velocity is 25m/s
Hence the formula of Kinetic energy is = 1 mv²
____
2
first we have to convert Kg into g
2 × 1000 = 2000gm
now put the value;
2000 × (25)² = 2000 × 625 = 1250000 gm²/s
Initial velocity is 25m/s
Hence the formula of Kinetic energy is = 1 mv²
____
2
first we have to convert Kg into g
2 × 1000 = 2000gm
now put the value;
2000 × (25)² = 2000 × 625 = 1250000 gm²/s
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