Question

a body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. what will be its potential energy at the end of 2 seconds

Answer 1

s=ut+1/2at^2
=40-20=20m
potential energy=mgh
=400J

Answer 2

at t= 2 sec
h= ut-½gt²
=(20*2)-½*10*2*2
=40-20
h = 20meter. (g=10m/s²)


potential energy=mgh
= 2*10*20
=400 jul......
hope this will help you...