Question

a body of mass 2 kg is tied to a free end of a string of length 1.5m and is revolved around a horizontal circle with the other end fixed. The body makes 300 rpm. Calculate the linear velocity, Centripetal Acceleration and the force acting on it.

Answer 1

Answer:

Explanation:

tension=centrifugal force

Answer 2

Given that,

Mass of the body, m = 2 kg

Length of the string, r = 1.5 m

Angular velocity of the body, $\omega=300\ rpm=31.41\ rad/s$

To find,

The linear velocity, centripetal Acceleration and the force acting on it.

Solution,

(1) Linear velocity in terms of angular velocity is given by :

$v=r\omega\\\\v=1.5\times 31.41\\\\v=47.11\ m/s$

(2) The centripetal acceleration acting on the body is given by :

$a=\omega^2r\\\\a=31.41^2\times 1.5\\\\a=1479.88\ m/s^2$

(3) Centripetal force acting on a body is given by :

$a=m\omega^2r\\\\F=2\times 31.41^2\times 1.5\\\\F=2959.76\ N$

Hence, this is the required solution.

Learn more,

Circular motion

https://brainly.in/question/2619889