Question

A body of mass 2 kg is tied to one end of a string of
length 1 m and revolved in a horizontal circle making
2 revolutions per second. Calculate the tension in
the string.​

Answer 1

Explanation:

hope it will help you bro

Answer 2

$\sf \:Given :\\\\m=2\:kg\\R= 1\:m\\f_{max}=2 \:rps$

$\\\\\sf v_{max}=R×w_{max}\\\\v_{max}=R(2πf_{max})\\\\v_{max}=1×2×\frac{22}{7}×2\\\\\underline{\underline{v_{max}=\frac{88}{7} \:m/s}}$

$\\\\\\\sf\:Maximum\:Tension\:force\:in\:string\\T_{max}=\frac{m{v_{max}}^{2}}{R}\\\\\therefore\:T_{max}=\frac{2×{(\frac{88}{7})}^{2}}{1}\\\\T_{max}=\frac{15,488}{7}=2212.57 \:N$

$\underline{\boxed{\sf{Tension\:on\:the\:string\:is\:2210.6\:N}}}$