Physics, asked by Tamanna1901, 11 months ago

a body of mass 2 kg moves in a circular path of radius 2 metre with constant speed of 20 metre per second the angular speed of the body is​

Answers

Answered by AneesKakar
4

Answer:

10 m/s.

Explanation:

Since, we know that the angular speed is the force which is experienced by the body which tends to move away from the center while moving around a circular path.

As, from the question we know that the body is of mass m = 2 kg, and speed of v = 20 m/s also the circular path is of radius r = 2 meter hence we know that the angular speed is given by the formulae of v=rω where ω is the angular speed of the body.

So, 20 = 2*ω or ω = 10 m/s which is the required angular speed of the body.


abhi178: correct your answer , question aksed to find angular speed rather than angular acceleration.
Answered by abhi178
4

answer : 10 rad/s

explanation : a body of mass , m = 2kg moves in a circular path of radius , r = 2m with constant speed , v = 20m/s .

then we have to find out angular speed of the body .

we know, angular speed is the rate of change of angular distance with respect to time.

so, \omega=\frac{\theta}{t}

in pure circular motion, relation between v , r and \omega

i.e., v = \omega r

so, 20 = \omega × 2

or, \omega = 20/2 = 10 rad/s.

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