Question

A body of mass 2 kg moving with velocity of 3 m per second collides head on which a body of mass 1 kg moving with velocity 4 metre per second after collision said the two bodies sticks together and moves with a common velocity which in which in its in the units of metre per second metre per second is equal to

Answer 1

Given mass of 1 st body m₁ = 2 kg

mass of 2nd body m₂ = 1 kg

Velocity of 1st body v₁ = 3 m/s  

Velocity of 2nd body v₂ = 4 m/s

Now momentum of 1st body p₁ = m₁v₁ = 2 × 3 = 6 m/s -----(1)

Momentum of 2nd body p₂ = m₂v₂ = 1 × (-4) = - 4 m/s ------(2)

(considering the bodies are moving towards each other)

Now from conservation of momentum we get

p₁+ p₂ = p -------(3)

Where p = combined momentum of the body after collision.

Reducing the values of 1 and 2 in 3 we get,

6 - 4 = (2+1) v

v = 2/3 = 0.67 m/s  

Answer 2

Explanation:

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