Question

A body of mass 2 kg travels along x axis, such that its position as a function of time is given by x(t) = at + Bt² 13, where α = + 3 m/s, B = 2 m/s² and 7 = 4 m/s ²³. The force acting on the body at time t = 3 s is​

Answer 1

solution is given in attachment

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Answer 2

Answer:

Force acting on the body at time t=3s is 8m/s²

Explanation:

x(t) = at + Bt² $Velocity=\frac{dx}{dt} \\ v=\frac{d}{dt} x(t)\\ v=\frac{d}{dt} (at+Bt^{2} )\\ v=a+2Bt\\ \\Acceleration=\frac{dv}{dt} \\ a=\frac{d}{dt} (a+2Bt)\\a=2B$

                      a=2×2=4m/s²

Force=ma

F=2×4

F=8m/s²

Hence Force acting on the body at time t=3s is 8m/s²