Question

A body of mass 20 kg is at rest. A force of 5n is applied on it. Calculate the work done in the first second

Answer 1

Answer:

0.625 J

Explanation:

Acceleration of body is

a = F / m

= 5 N / (20 kg)

= ¼ m/s²

Displacement covered in first second is

S = ut + ½at²

= (0 m/s × 1 s) + [½ × ¼ m/s² × (1 s)²]

= ⅛ m

Work = Force × Displacement

= 5 N × ⅛ m

= ⅝ N m

= 0.625 J