Question

A body of mass 20 kg moving with a velocity of 10 m/s collides with another body of mass 40 kg moving in the same direction with velocity of 5 m/s.
a)if both the bodies stick together after collision find the common velocity?
b)if heavier body moves with speed 8 m/s opposite to the lighter body after the collision. find the velocity of lighter body

Answer 1

Hello friend
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Given:

Mass of the first body (m1) = 20kg

Mass of the second body (m2) = 40kg

Initial velocity of the first body(u1)=10m/s.

Initial velocity of the second body(u2)=5m/s.

a.) Common velocities of both the body.

Let's v1 and v2 be the common velocities of the body.

means, v1=v2=v

So,by applying the formula

m1u1 + m2u2 = m1v1 + m2v2

Now put the values,

(20 x 10) + (40 x 5) = (20 x v) + (40 x v)

200 + 225 = v(20+40)

425 = 60v

v = 425/60

v = 7.08m/s

therefore the common velocities is 7.08m/s as well as we can write It 7m/s also.

I hope this will helps you.

Thanks.