Question

ethyl iodide undergoes sn2 reaction faster than ethyl bromide...why?

Answer 1

when we compare both example we check always ligand and as we called leaving group as halogen family top to down goes as the reactivity faster in sn2 as more the good leaving group as iodine is good leaving group than bromine so sn2 reaction is faster

Answer 2

Explanation:

• Basicity decreases with increase in size
• Iodine is a better leaving group  

Thus ethyl iodide undergoes SN2 reaction faster than ethyl bromide

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