Question

A body of mass 25kg is initially at rest. A force of 150N is applied
to the body. Find the velocity of the body after 10seconds and the
distance covered by it in 10seconds.
​

Answer 1

✬ Final velocity = 60 m/s ✬

✬ Distance covered = 300 m ✬

Explanation:

Given:

• Initial velocity (u) is 0 m/s.
• Mass (m) of body is 25 kg.
• Force (f) applied on body is 150N.
• Time (t) given is 10 seconds.

To Find:

• What is the velocity and distance covered by body in 10 seconds ?

Formula to be used:

• F = ma { For acceleration }
• v = u + at { For final velocity }
• s = ut + 1/2at² { For distance }

Solution: As we know that

★ Force = Mass $\times$ Acceleration ★

$\implies{\rm }$ 150 = 25 $\times$ a

$\implies{\rm }$ 150/25 = a

$\implies{\rm }$ 6 m/s² = a

So, The acceleration of body is 6 m/s².

Now finding final velocity

$\implies{\rm }$ v = u + at

$\implies{\rm }$ v = 0 + 6 $\times$ 10

$\implies{\rm }$ v = 60 m/s.

So, The final velocity of body after 10 seconds is 60 m/s.

Therefore, Total distance covered is

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 $\times$ 10 + 1/2 $\times$ 6 $\times$ 10²

$\implies{\rm }$ s = 0 + 3 $\times$ 100

$\implies{\rm }$ s = 300 m

So, The total distance covered by the body after 10 seconds is 300m.

Answer 2

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