Question

A body of mass 2kg collides with a wall with speed 100m/s and rebounds with same speed. if time of contact is 1/50sec ,the force exerted on wall is

Answer 1

u = 0 m/s
v = 100m/s
t = 1/50 sec

using first equation of motion
v = u+at
=> 100 = 0+a(1/50)
100 = a/50 => 5000 m/s²


force = mass × acceleration
force = (2 × 5000) N
force = 10000 newtons

hope this helps

Answer 2

The force exerted on the wall is 2 × 10⁴ N

Explanation:

Let the force exerted by the wall is F

Impulse by the wall = F × t

Where t = 1/50 s

Mass of the particle m = 2 kg

Initial velocity u = 100 m/s

velocity after impact v = -100 m/s (Since, it will rebound in opposite direction, hence negative sign)

We know that

Impulse = Change in momentum

$F\times t=mu-mv$

$\implies F\times\frac{1}{50}=2\times 100-2\times (-100)$

$\implies F\times\frac{1}{50}=200+200$

$\implies F=50\times 400$ N

$\implies F=20,000$ N

$\implies F=2\times 10^4$ N

Hope this answer is helpful.

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