A body of mass 2kg fallls freely from rest through a height of 50m and come to rest having penetrated 5.0m of sand. Calculate:
i. The velocity which the body hit the sand.
ii. The time taken in falling
iii. The average force exerted by the sand in bringing the body to rest
Answers
Answered by
4
mass of the body = 2 kg.
height = 50 metres.
initial velocity of body = 0 m/s.
final velocity of body = ?
We know that acceleration due to gravity = 9.8 m/s².
according to third equation of uniformly accelerated motion=> v² = u²+2gh
v² = 0 + 2×9.8×50.
v² = 980
v = √980
v = 31.3 m/s
♦••••••••••••••••••••♦
according to first equation of uniformly accelerated motion that is v = u + g t.
31.3 = 0 + 9.8 x t
time = 31.3 / 9.8.
time = 3.19 seconds.
♦••••••••••••••••••••♦
PLEASE MARK IT AS A BRAINLIEST ANSWER.
height = 50 metres.
initial velocity of body = 0 m/s.
final velocity of body = ?
We know that acceleration due to gravity = 9.8 m/s².
according to third equation of uniformly accelerated motion=> v² = u²+2gh
v² = 0 + 2×9.8×50.
v² = 980
v = √980
v = 31.3 m/s
♦••••••••••••••••••••♦
according to first equation of uniformly accelerated motion that is v = u + g t.
31.3 = 0 + 9.8 x t
time = 31.3 / 9.8.
time = 3.19 seconds.
♦••••••••••••••••••••♦
PLEASE MARK IT AS A BRAINLIEST ANSWER.
Similar questions