Question

A body of mass 2kg falls from rest.what what will be its kinetic energy during the fall at the end of 2 sec?

Answer 1

Velocity after 2 seconds is
v = u + at
= 0 + (9.8 m/s² × 2 s)
= 19.6 m/s

Kinetic energy after 2 s = 0.5 mv²
= 0.5 × 2 kg × (19.6 m/s)²
= 384.16 joules