Question

A body of mass 2kg is at rest.500j work done on it raises it by 10m.what is its speed

Answer 1

Answer:

10√5 m/s

Explanation:

Work = Force × Distance

Force = Work/Distance

Fₙₑₜ = 500 J / (10 m)

Fₙₑₜ = 50 N

Acceleration = Force / Mass

= 50 N / 2 kg

= 25 m/s²

Speed at the end of 10 m is

v = √(u² + 2aₙₑₜS)

= √[0² + (2 × 25 × 10)] m/s

= √500 m/s

= 10√5 m/s