A body of mass 2kg is at rest.500j work done on it raises it by 10m.what is its speed
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Answer:
10√5 m/s
Explanation:
Work = Force × Distance
Force = Work/Distance
Fₙₑₜ = 500 J / (10 m)
Fₙₑₜ = 50 N
Acceleration = Force / Mass
= 50 N / 2 kg
= 25 m/s²
Speed at the end of 10 m is
v = √(u² + 2aₙₑₜS)
= √[0² + (2 × 25 × 10)] m/s
= √500 m/s
= 10√5 m/s
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