a body of mass 2kg is at rest on a smooth horizontal surface. a force of 5N is applied horizontally on the body. how much work the body will do in 5 seconds?
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as per given data
F= 5N , m= 2kg,
and according to Newton's laws
net force,F=ma
a=F/m=5/2=2.5 m/s sq.
where s is displacement
so, s= 0+0.5 * 2.5* 25=31.25
and, work = force * displacement
=5* 31.25
=156.25 joules
F= 5N , m= 2kg,
and according to Newton's laws
net force,F=ma
a=F/m=5/2=2.5 m/s sq.
where s is displacement
so, s= 0+0.5 * 2.5* 25=31.25
and, work = force * displacement
=5* 31.25
=156.25 joules
vikramaditya85011:
vo 0.5. kah se. aaya formula me. ?
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