Physics, asked by vikramaditya85011, 1 year ago

a body of mass 2kg is at rest on a smooth horizontal surface. a force of 5N is applied horizontally on the body. how much work the body will do in 5 seconds?

Answers

Answered by askavi
3
as per given data
F= 5N , m= 2kg,
and according to Newton's laws
net force,F=ma
a=F/m=5/2=2.5 m/s sq.

s = ut + 0.5a {t}^{2}
where s is displacement
so, s= 0+0.5 * 2.5* 25=31.25
and, work = force * displacement
=5* 31.25
=156.25 joules

vikramaditya85011: vo 0.5. kah se. aaya formula me. ?
askavi: 1/2=0.5 :)
askavi: as in formula writing option there was no option for writing 1/2
askavi: u can refer third laws of motion
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