Physics, asked by mahmoodah6612, 1 year ago

A body of mass 2kg is lifted up to a height of 10m and then allow to fall freely. Find the potential and kinetic energy that it just has before touching the ground

Answers

Answered by MarilynEvans
14
 \Huge{\boxed{\red{\mathbb{QUESTION}}}}

A body of mass 2 kg is lifted up to a height of 10 m and then allow to fall freely. Find the potential and kinetic energy that it just has before touching the ground.

 \Huge{\boxed{\purple{\mathfrak{ANSWER}}}}

 \bold{Given\:that,}

Mass = 2 kg

Height = 10 m

Final velocity = 0 m/ s

 \bold{Assumption\::\:-}

Acceleration due to gravity =  10 m/s^2

Here the intial K.E will be 0 as the final velocity is 0.

Initial K.E. = 0 J

 \bold{By\:using\:P.E.\:formula.\:That\:is,}

Intial P.E = mgh

Intial P.E. =  2 \times 10 \times 10

 \Large{\bold{P.E.\:=\:200\:J}}

When the body is dropped just before touching the ground. Then the,

Height = 0 m

Now,

Final P.E. = mgh

Final P.E. =  2 \times 10 \times 0

Final P.E. = 0 J

According to the law of conservation of energy,

Total intial energy = total final energy

=> 0 + 200 = 0 + final K.E.

=> Final K.E. = 200 J

 \Huge{\boxed{\pink{K.E.\:=\:200\:J\:and\:P.E.\:=\:0\:J.}}}

Swarup1998: Awesome answer! :)
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