a body of mass 2kg is moving along a straight path with the velocity of 2m/s. the external force acting on the body is.
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Given that F=i-2j, we can say that the acceleration will be a=0.5i-j since a=
m
F
and mass is given to be 2kg in this question. After this, we calculate the velocity after breaking initial velocity V=3i+4j into its components. Thus, in the x-direction, Vx=u(x)+a(x)×t=3+(0.5×4)=5 m/s.
In the y direction,Vy=u(y)+a(y)×t=4−4=0
Therefore we get answer C, which is 5 m/s in the x direction.
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