a body of mass 2kg is moving along postive x axis with a velocity of 5ms.now a force of 10root 2 N is applied at an angle of 45 degrees with x axis.its velocity after 3 sec is?
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F=10N
a=10/2=5m/s^2
for t=3sec
we have,
v=ut+1/2at^2
=>v=5*3+1/2*5*9
=>v=15+1/2*45
=>v=37.5m/s
a=10/2=5m/s^2
for t=3sec
we have,
v=ut+1/2at^2
=>v=5*3+1/2*5*9
=>v=15+1/2*45
=>v=37.5m/s
dilwar10:
so 10√2*sin45degree
will be 10
hmmmmm but the final answer should be 25 ms
how could it be?
can u plz explain
in the key for these question its given 25 is the answer.........am asking u the solution.....coz i din get
formula will be v=u+at
but then also ans will be 20
yea ur rght
pleasure is mine
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