Question

a body of mass 2kg is projected vertically upward with velocity 2 ms^-1.kinetic energy of the body before striking the ground​

Answer 1

Answer:

KE = 1/2mv^2

KE =1/2×2×2^2

KE =4

Answer 2

Answer: Here:

m=2kg

v=2m/s or 2ms^-1

Kinetic energy(Ek)=?

By using :

Ek =1/2 mv2 (2 is here square of v)

=1/2 2×22

Or 2/2 2×22

=8joule will be its Kinetic energy