Question

a body of mass 2kg moves down quadrent of circle radio's 4 m the velocity reaching lowest point 8 ms-1 the work done afainst friction is
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Answer 1

Loss of energy is 14.4 J

Loss of energy is 14.4 JExplanation:

Loss of energy is 14.4 JExplanation:Given,

Loss of energy is 14.4 JExplanation:Given,Mass, m = 2 kg

Loss of energy is 14.4 JExplanation:Given,Mass, m = 2 kgRadius,r = 4 m

Loss of energy is 14.4 JExplanation:Given,Mass, m = 2 kgRadius,r = 4 mVelocity , u = 8 ms-1

We know that,

We know that,Loss of energy,

We know that,Loss of energy,= mgr-1/2×m×u2

= 2×9.8×4-1/2×2×82

=  78.4-64

= 14.4 J

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