A body of mass 2kg moving on a horizontal surface with speed v initial =1 meter/sec enters a rough surface patch ranging from X=0.5m to X=1.5m. If a body comes to rest after crossing the patch then find the retarding force on the body.
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W= Change in kinetic energy
F.S= 1/2 m (v^2 - u^2)
-F ×(1.5- 0.5)=1/2 ×2×(0- 1)
-F=-1
so retarding force is 1N
F.S= 1/2 m (v^2 - u^2)
-F ×(1.5- 0.5)=1/2 ×2×(0- 1)
-F=-1
so retarding force is 1N
ayaan6129:
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